Parralell / split question

[zionstrat]

Re: Parralell / split question

Wow, thanks for the spin-a-split info, guys.

You'd still want to use a logarithmic-taper pot for this, right? Because it's basically just a volume control for one of the coils?

Frankly, to me it doesn't matter. The Sweet spot for spin a split falls in a very small range, so I usually dial it in and leave it there. One thing to note is my spinach splits are by passable and often I will measure the spin a split value and replace the spin a split with a resistor bundle of the same value and switch it in and out.

And yes between the noise reduction and tone, we do a lot more parallels and partials than we do full splits.

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[Clint 55]

Re: Parralell / split question

Wow, thanks for the spin-a-split info, guys.

You'd still want to use a logarithmic-taper pot for this, right? Because it's basically just a volume control for one of the coils?

Splits appear to react to the absolute amount of resistance rather than the proportion of the sweep like a volume. 10k will split it the same amount regardless of what the value is at full. For this reason, you have to use a small value pot to get any kind of taper. I've tried everything and found that a 50k no loaded pot works best.

[zizyphus]

Re: Parralell / split question

Splits appear to react to the absolute amount of resistance rather than the proportion of the sweep like a volume. 10k will split it the same amount regardless of what the value is at full. For this reason, you have to use a small value pot to get any kind of taper. I've tried everything and found that a 50k no loaded pot works best.

Also, heed the "no load" part

I did a spin-a-split mod on some of my humbuckers without a low-resistance pot (probably around the 50k that Clint suggested), and it sounded MUDDY as all hell because of all the treble that grounded out

[Clint 55]

Re: Parralell / split question

Yeah if you don't no load it, the humbucker will never be full series. You'll lose the gainy sound of the full hum in series because it will always be partially split.