Recent content by freefrog

+1. Regarding a same pickup in different guitars: powerful humbuckers tend to put the same loud voice in any instrument and are often played overdriven, which tends to mask the difference between instruments. It doesn't deny potential tonal differences due to scales, pickup locations relatively...

+1 about the inductance. Tell us what you think about the sound.

Cap value depends on the effect wanted. Count 40 or 45 pF per foot of cable to emulate. Has to be wired between hot and ground of the guitar or of pickups themselves. Albeit I had found it by myself when I was young, it's an old recipe. It was allusively evoked in Duncan FAQ decades ago - or...

Glad you like it. Enjoy!

Copper plates are a source of eddy currents and might alter the response of the sidewinder coils used in these Mojotone, AFAIK. I'd try some plastic bP first.

Try a Volu-tone lap steel if you want to know... but it doesn't go without risks. :p https://reverb.com/en-fr/item/48166137-volu-tone-lap-steel-and-5pp-amp-set-with-energizing-switch-1935-rare Putting permanent magnets perpendicular to the strings and far from the coils shouldn't do much...

A thing is that capacitors can have extremely different effects on hi freq comb filtering with only a few pF of difference... and that all coils don't react in the same way, even with pickups of a same model (parasitic capacitance being something variable even with the most precisely controlled...

Split always gives half of the inductance and parallel, 1/4 of it. So, normally, parallel is quieter (electrically). And it shouldn't have a "hollow sound": if anything, it "symmetrizes" the response of both coils, cancelling the slight comb filtering effect always due to series path with a 4...

Understood. I was just sharing about what it gives exactly (no negative vibes in my comments). ;-)

To repeat my usual stance, parallel wiring divides the inductance in series by approximatively 4. It shifts up the resonant frequency and lowers the output, yes (since it focuses the energy of the transducer in higher frequencies, weakening the fundamental notes accordingly)... And to share...

it would give 187,5k, like twice 375k pots in parallel. :-)

Hello, welcome onbard and thx for your testimonial. In the sentence above, I guess you meant 1.5M? Because a 1.5k would give a pot value of 1.495k. To change a 500k pot in a 400k one, it would require a 2M resistor. Handy calculators can be found online BTW. Here is an example among others...

Seth's are my favorite Duncan HB's for various reasons (including the generosity of Seymour with Seth Lover and his family) but to me, they're less P.A.F. clones than a unique model, where a vintage design meets that always musical "Duncan voicing" that we all love here. The old Vintage Guitar...

Which doesn't cancel the effects of magnets as explained in my previous post. ;-) EDIT - That said: increased inductance and eddy currents are there for the pickup hosting the magnet(s)... A separate coil won't have its inductance increased by the magnet(s) of another pickup nor will be...

Not watched the video but sure, a coil will be sensitive to vibrating strings as soon as they're magnetized. This "proposition" is generally not true ["generally" meaning: for coils directly paired with magnets. Regarding separate coils, see my afterthought comment in post 10 below]. :-)...