frtbzz
New member
OK I did the cathode follower thing on my '79 50 JMP. I soldered resistors from pin 1 to ground(pins 1 and 8 tied together) My resistors are not exactly 1 ohm (1.2). I have 390 VDC on pins 3. I'm biasing up the amp.
70% .7X25watts/390=44.8ma's. Now since my resistors are 1.2 I multiply 44.8 by 1.2 which gives me 54mv's. Am I doing this right? In this case 44.8ma's=54mv's with my 1.2 resistors?
Can you please correct me if I made any errors along the way.
By the way there is a 4ma difference when I take the reading between the 2 power tubes. Left=51mv Right=55mv.
70% .7X25watts/390=44.8ma's. Now since my resistors are 1.2 I multiply 44.8 by 1.2 which gives me 54mv's. Am I doing this right? In this case 44.8ma's=54mv's with my 1.2 resistors?
Can you please correct me if I made any errors along the way.
By the way there is a 4ma difference when I take the reading between the 2 power tubes. Left=51mv Right=55mv.
