Changing speaker ohms

Yes, you can plug the INPUT jack to the amp, and use the THROUGH jack to go to another cabinet, I am 99.9% sure that is a parallel connection, so when you plug into another 8 ohm cab you have a total impedance of 4 ohms, which is too low for your Super Sonic 22.
 
Yes, you can plug the INPUT jack to the amp, and use the THROUGH jack to go to another cabinet, I am 99.9% sure that is a parallel connection, so when you plug into another 8 ohm cab you have a total impedance of 4 ohms, which is too low for your Super Sonic 22.

Ok thanks for the help with that do it's looking like I might not be able to hook both cabs up together but I guess I can use them separately or maybe replace one of the v30's with the A type...
 
if the two v30s are 16ohms wired parallel, which is what i would assume for a 8ohm 2x12 cab, you cant just swap the 8 ohm speaker in without changing the impedance of the cab
 
well, you can, but it wont be the same impedance. almost any time you mix two cabs, you are always doing so in parallel wiring. within one cab, you can have series or parallel wiring. you need to understand how mixing impedance, whether its two speakers, or two cabs, works before going any further to save yourself some frustration
 
well, you can, but it wont be the same impedance. almost any time you mix two cabs, you are always doing so in parallel wiring. within one cab, you can have series or parallel wiring. you need to understand how mixing impedance, whether its two speakers, or two cabs, works before going any further to save yourself some frustration

I was assuming that the 2 v30's we're both 8 ohm but I'm not sure I will find out. So is it not possible to have 2 8 ohm speakers in a cab needing 8 ohms of resistance from the amp?
 
correct. 8 + 8 can either be 16 ohms (in series) or 4 ohms (in parallel). you can mix an 8 ohm speaker with a 16 ohm speaker in a cab but you end up with an impedance that is outside of what amps usually want to see. doesnt mean it cant be done, but should be done with caution and understanding of what you are doing and how your amp will deal with it and how the mismatch will dictate how the speakers interact
 
well, you can, but it wont be the same impedance. almost any time you mix two cabs, you are always doing so in parallel wiring. within one cab, you can have series or parallel wiring. you need to understand how mixing impedance, whether its two speakers, or two cabs, works before going any further to save yourself some frustration

Probably best to stick to basics, no, it's not a good idea to mix impedances.

Yes, but it also splits the power to the speakers unevenly.
 
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Probably best to stick to basics, no, it's not a good idea to mix impedances.

Yes, but it also splits the power to the speakers unevenly.

Your right. I'm beginning to understand how impedance/resistance works, I have a question how are the speakers usually wired in a 4x12 cab?
 
My Carvin 4x12 is wired series/parallel with 4 16ohm speakers, giving me a 16ohm cab.

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My Carvin 4x12 is wired series/parallel with 4 16ohm speakers, giving me a 16ohm cab.

Sent from my SM-A115A using Tapatalk

Can you please explain how you get 16 ohms of resistance from the 4 speakers? What are the resistances of the 4 speakers? By series/parallel do you mean two are wired in series and 2 in parallel? Forgive me for all the questions I'm trying to get the math down for calculating total ohms or impedance.
 
As he said, the speakers are 16 ohms each. 2 sets of 2 are wired in parallel, so 2X 8 ohm loads, then those are wired in series to give a total of 16 ohms.

https://www.electronics-tutorials.ws/resistor/res_3.html

https://www.electronics-tutorials.ws/resistor/res_4.html

https://www.electronics-tutorials.ws/resistor/res_5.html

Thanks for the links that was very helpful of you. I saved those if I need to go back to them but I now have a better understanding of the matter. Thank you and everyone else that helped me to learn about this and answered the annoying newb questions there is a first for everything it's kind of embarrassing to not have learned this earlier as I've been playing since I was 14 but I've needed to connect speakers before as I used cheap SS combo practice amps for most of the time I've been playing i just recently was able to afford tube amps.
 
You can change the speaker cab to hold to whatever speaker and speaker impedance you want -but you want to see the options of the output of your amplifier feeding it to match that ideally -and that depends on how the transformer is tapped and broken out.
 
Can you please explain how you get 16 ohms of resistance from the 4 speakers? What are the resistances of the 4 speakers? By series/parallel do you mean two are wired in series and 2 in parallel? Forgive me for all the questions I'm trying to get the math down for calculating total ohms or impedance.

Resistance is Ohms law baby!

Parallel:
1/Rtotal = 1/R1 + 1/R2 + 1/R3 . . . etc.

Series:
Rtotal = R1 + R2 + R3 . . .


So with 4 16 ohm speakers you do this:

Parallel:
1/R12 = 1/R1 + 1/R2
1/R12 = 1/16 + 1/16 = 2/16 = 1/8

So we know the resistance of speaker 1 and 2 in parallel is 8 ohms.

Same equation works out to the same value for the resistance of speaker 3 and 4 in parallel - 8ohm

Then you wire the parallel speakers 1/2 and 3/4 in series with each other to get:
Rtotal = R12 + R34
Rtotal = 8 + 8
Rtotal = 16 ohms


Simple!
 
16 Ohms from a 4x12 cab with four 16 Ohm speakers is quite common. The series/parallel thing sounds confusing, but it just means two pairs.
Two of the speakers are wired in series to give 32 Ohms impedance. The other two are wired the same.
Then the two 32 Ohm pairs are wired in parallel with each other to give an overall cabinet impedance of 16 Ohms.
 
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