Changing speaker ohms

actually, i think its usually two 16 ohm speakers wired in parallel, then the two parallel sets wired in series but the end result is probably about the same.

its cool if you have the modern switching jack for a 4x12 and four 16ohm speakers. with two pairs of 16ohm speakers wired parallel, you can run each pair separately at 8ohms, or both pairs in series for 16ohms, or both pairs in parallel for 4 ohms. i used on of those plates with two 8ohm speakers so get the same options, just with two speakers instead of four
 
After my degree I know how to integrate, derivate, do matrix algebra, calculate heat and mass transfer, and use Laplace transforms . . . but almost the only thing I've applied in the real world is Ohms law. :P

I can still spell calculus, and I remember thinking integration and deviation wasn't that hard when I was learning it, but I haven't used it in decades, so I can no longer claim to "know" it.
 
Can you please explain how you get 16 ohms of resistance from the 4 speakers? What are the resistances of the 4 speakers? By series/parallel do you mean two are wired in series and 2 in parallel? Forgive me for all the questions I'm trying to get the math down for calculating total ohms or impedance.
I have two pairs wired in series for 32 ohms. Then those pairs are wired parallel to each other, giving 16 ohms total impedance.

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