Obviously.Class A is for awesome right?![]()
That was also my question. In the end it will, the question is just how much? Let's simply assume the transistors act like diodes when they are in bypass mode, that means there will be series resistances, and a small capacitance, the key is minimizing them to tame influence. In the end capacitance kills and is the most important, so the key is getting that one down. Also the resistance should not be too high either...How is that "mosfet relay" then supposed to not change impedance?
That was also my question. In the end it will, the question is just how much? Let's simply assume the transistors act like diodes when they are in bypass mode, that means there will be series resistances, and a small capacitance, the key is minimizing them to tame influence. In the end capacitance kills and is the most important, so the key is getting that one down. Also the resistance should not be too high either...
Looking at the datasheet for the CD4053 the capacitance when on is max 20pF, so that's good. The resistance is 240 Ohm max, 125 typical, that is good too. The lowpass cutoff will be 7*10^7 Hz, which is beyond the sonic spectrum. That means we're safe. And only with a crazy low imput impedance of the subsequent pedal/amp you will notice anything of the series resitance, right? Even when using 10 pedals of this type you should still be ok... So I guess it will perform just like a true bypass pedal in the end. Or did I overlook something?
I bought an MXR Submachine fuzz pedal recently. While I love it, the box, websites, and demo videos advertise that it is true bypass, however the back of the user's manual says that it is buffered bypass in the specs.
When I tested the pedal in person, I discovered that it is not true bypass. I personally don't really care about whether a pedal is buffered or has true bypass, but some people do care.
And regardless of the timeless debate on the issue, I think MXR should be more honest about their products. Still an awesome pedal, though.
Have you guys ever caught B.S. like this from a guitar, amp, or pedal company? Do you think they're deliberately misleading people, or do you think they are just uneducated about their own products?
there's an old saying that goes.........I dont lie, I sell! pretty much sums that up.:scratchch
I guess not. At least not in the sense of having an active element in the signal path. To me it looks like it just acts like a small resistor and capacitance, just like any cable would. However the resistance is somewhat higher than normal. Too me that's it. I'm not completely sure though, I haven't looked into the internal workings of this device.But that means that, even in bypass mode, it is still an active element.
I think it would... But again, I'm not sure.To ask differently, if you were to place a load capacitor to lower the pickup's resonance peak frequency before and after such a bypass, it wouldn't work after it, no?
True bypass is called a guitar cable plugged from amp to guitar with nothing in between!
I guess not. At least not in the sense of having an active element in the signal path. To me it looks like it just acts like a small resistor and capacitance, just like any cable would. However the resistance is somewhat higher than normal. Too me that's it. I'm not completely sure though, I haven't looked into the internal workings of this device.
I think it would... But again, I'm not sure.
Hmm, hold on. The capacitance is in series (the signal flows through it), no?
No way, a pf range capacitance in series would be a highpass-filter that would only let all the really high frequencies through. The listed capacitance will surely be parallel as well. So it really is like a cable.
Yes, in effect it is comparable to using an extra patch cable, which also has something like 80pf/meter = 25pf/ft.Fair enough then. 20 pF would be acceptable as an additional load.
My Vox guitar cable has 0.41 nF, so that would be 5% more load.
Yes, in effect it is comparable to using an extra patch cable, which also has something like 80pf/meter = 25pf/ft.
To fully do an honest comparison you'd also have to measure the resistance and capacitance of an average true bypass guitar pedal and compare. The 3pdt switch can have some capacitance, but the good ones usually do not...
To me that's basically asking, does putting it after or before a long cable make a difference. If yes, then yes it may (although it is more comparable to a short cable) make a difference.Now, a bit of load is OK with me.
I just can't wrap my head about the concept that impedance after this circuit is the same.
If you were to put load capacitors before or after this bypass, would they behave the same way?
Still want to testTo me that's basically asking, does putting it after or before a long cable make a difference. If yes, then yes it may (although it is more comparable to a short cable) make a difference.
I feel the thing that gets to you is: 'it's active'. But it is not really. In the end you can view it as a simple diode put in line with your signal, when bypassed. That's about it. In reality diodes have a stray capacitance and series resistance, so they are not theoretical, ideal diodes. That about the comparison between a real shorting switch = true bypass and a 'diode' short = this 'chip-bypass'. I hope that comparison helps a little bit
That's indeed where the comparison is not quite sufficient. In the end it functions as a diode with an added (non-used) electrode when in bypass mode. Hence the capacitance in parallel. The electrode is not 'functional' in the bypass mode, but it lead to some capacitance none the less.OK, but that doesn't mix with saying that the load capacitance is parallel to the signal. How can a diode in series have a capacitance in parallel?