Re: crazy question on decibels.
The best way of using "Watts" as a mesurement of how suitable a product will be for a given situation is when you are buying a space heater.
You're right in that when thinking of how loud something will be you should be thinking in dB.
Keep in mind that 99.999% of the numbers used when describing the "wattage" of an amplifier is marketing bull poo, even in the world of pro audio.
But as a rule of thumb (but not getting too technical),
Every doubling of amplifier power results in a 3dB increase in SPL (Sound Pressure Level) at a given distance.
Every doubling of speaker cone area (With equal power applied) results in a 3dB Increase in SPL at a given distance.
As an example.
Say an amplifier is applying a signal of 50watts to a 1x12 speaker. at a distance of 10 meters the SPL meter reads 100dB.
If you then apply 100watts to the same 1x12 speaker, at 10 meters the SPL meter will read 103dB.
If you apply 50 watts to 2x12 speakers, at 10 meters the SPL meter will read 103dB
And if you apply 100 watts to the 2x12, at 1 meter the SPL meter will read 106dB (Since you've doubled both the power and the speaker cone area)
So say for your case you use 2 x 20watt heads each into a 1x12 speaker.
You essentially have a 40watt amplifier into 2x12 speaker so you theoretically have up to 6dB more headroom.
Saying how much headroom an amp or amp setup has is just another way saying how much potential output the amp has before it starts to distort, or breakup. So by increasing the amount of power and/or speaker cone area you will increase headroom.
But keep in mind that increasing speaker cone area will only work to the point until comb filtering (phase cancellations) come into play.
This is a really basic explanation as the physics of sound is much more complicated than simple numbers but hopefully this helps you
I heard a great quote from someone in the pro audio industry that went something like this
"A complex question is easily answered by a simple-easy to understand WRONG answer!"