When humbuckers are wired with a volume and tone, in general they are both 500k pots. My understanding is that two 500k pots equals a resistance of 250k. If that is the case, and you only want a volume to control the humbucker without the tone, should you simply use a 250k pot? Or, is it more complicated? What pot should I use for a volume with no tone on my humbucker?
A single 500k volume pot = roughly 2dB added to the resonant peak of a humbucker. It gives more sizzle, in the EVH fashion.
EDIT- If you want to see the action of resistive loads on resonant peaks, see for instance the fig. 14 in this page:
http://buildyourguitar.com/resources/lemme/
There's many other pages of the same kind showing the same thing but this one was among the firsts so I share the link.
A single 250k volume pot gives
exactly the same resonant peak than a 500k volume pot + 500k tone control
when pots are full up. The differences are...
-harmonics,
a tiny wee bit affected by the tone capacitor, even when the tone pot is full up. This difference is minuscule and might even be not really perceptible in some situations but it's there (lab gear and 5Spice sims can detect it);
-the TAPER of the volume pot and its darkening action... a 250k @ half its resistance puts only 125k between hot and output but also only 125k between output and ground so it darkens the sound more when lowered.
If you want to mimic the -2dB rounding action @ resonance of a 500k tone pot full up without loosing the taper of a 500k volume control, put a 470k or 520k resistor in series with a 22nF (0.022µF) then solder the whole from output to ground. I've done that sometimes (and legends tell that EVH had hidden a fixed tone pot in the cavity of his Frankenstrat. If he had used a trim pot or a resistor, it would have been the same).
FWIW: my two worthless cents, not far from the price of a resistor.
