Re: tone control
sanrafael said:
Well, I think what I am saying makes sense, but maybe I have misunderstood something.
When you place a resistance across a pup to damp the resonance, the significant effect is at frequencies near the resonance. If you place a series RC across the pup, and the impedance of the C at the resonant frequency is small compared to the resistance of the R, then the effect is essentially the same. For example, a .02 microfarad capacitor (typical of a tone control) has an impedance of 1592 at 5000 Hz. This is much smaller than 250K or 500K and so with either pot on 10, the series RC circuit would act almost like the resistor by itself.
I think that the operation of the usual guitar tone control is this: as you turn the pot from 10 down, at first the effect comes from loading the pickup with the decreasing resistor value. But as the pot value continues to decrease, the capacitor starts to matter. With the pot at zero, the capacitor drastically alters the resonant frequency of the pickup., but the damping is very high with this value of C because of the resistance of the pickup. (At 500 Hz, the impedance of the C might be 15,920, only somewhat greater than the resistance of many pickups.)
First of all approximating all values for practicality, a straight resistor will only really effect the amplitude of the pups res Fc peak, unless you get it very low in which it will start to decrease the output level voltage, of course we aren't talking about that. If you have a capacitor and resistor in series, and that series connection is placed in parallel with the pup (as we are talking here) ... then with a tone pot of 500k (if we assume a linear response to frequency) the the total added loading is the Xc of the cap plus the 500k of the pot. Now at 5kHz. we have (500k+1.6k) 501.6k, at 10kHZ, we have (500k+0.8K) 500.8k; going the other way, at 2.5kHZ. we have (500k+3.2k) 503.2k , and continuing down in octaves .. 506.4k, 512.8k, 525.6k, 551.2k,602.4k (ending at 78.125Hz., below the low
E'sfundamental Fc).
The difference in
load on the pup changes with Fc, from 10kHz. (more isn't really practical for guitar) to slightly below the fundamental of the lowest note is 101.6k ... higher frequencies loaded more than the lower ones.
This results in the higher of the higher Fcs being attenuated more (I mean that is what a LPF does), the difference between the two is very subtle, a straight resistor serves to only dampen the pup's res Fc, the res Fc shift of the pup only happens a low levels of resistance (tone pot settings), as the resistance damps that peak, however in both cases once that resistance is low enough to to allow the res Fc shift it will do that ... BUT it also attenuates the Fcs above it, the -3dB corner remains the same regardless of the pup resonance with the cap, it will stay determined by the impedance of the source plus any controlling resistance (pot setting), which when to much will dampen that new res Fc peak (which will be below the cut-off Fc of the filter). What will not change is that when the control is moved it will shift both the corner -3dB Fc of the filter as well as it's lower corner Fc of the maximum attenuation shelf.
The difference at 10 is subtle at best, and shows up differently from pup to pup ... It is worth noting that they are not the same though ... If you were to find the pups res Fc, and place a resistor (R1) of some value there, then exchange that for a resistor (R2)in series with a cap whose R2+Xc equalled R1, then you'd find that the RC has a bit less overall brightness then the R alone (this effect becomes more noticeable depending where the pups res Fc peak is located, as pup's with high res Fc peaks may not be perceived as bright as some a bit lower).