Re: Thought of a cool new STRAT wiring....
Capacitors block DC once charged, take an isolated cap, clip the probes to it and at first you'll see it's resistance read very low, then the resistance will start to increase more and more as the cap charges, until finally the resistance reaches infinity (or a very high resistance amount). At that point the cap will be blocking the DC from passing thru it. Now I have seen some caps leak DC, but what you're describing here would be a cap that has shorted, or partially so ... That wouldn't be the case here since everything is working correctly.
What you have described here is equal to taking two resistors in series (one volume and one tone), clipping one probe to one end, and the other to the middle connection, and leaving the end of the other resistor floating unconnected ... *But it is connected to ground* you say, thus putting both resistors (pots) in parallel ... yes, but it's connected to ground by *thru a capacitor* That cap looks like an open circuit to the DC, thus the connection is not completed to put them in parallel ... the meter doesn't see the other resistor (pot). Now, it will at first ,until the cap charges ... See?
The only way I can see the meter seeing the other pot , given the wiring and probe placement that you have explained here, is if you had the common probe (black) clipped to ground, and the hot probe (red) { the polarity doesn't matter here, only given as a referrence mind you for others viewing this} clipped to the wiper of the one pot with both controls at *10*. However, that would be placing both pots in series with each other, and not in parallel.
This means that the cap is passing DC, completing the parallel circuit between the two pots, with the knobs at 10 the DC has to go thru the resistance of the pots, so that lengthens the charge time of the cap.
Try this ... Disconnect the cap from ground, and leave it disconnected ... then take the readings (that is, if you actually want to check it, otherwise just roll with it). Anyway, that's why they cap should affect the readings, I'm at a loss as to why you are getting the readings that you are; However, what you are doing with the resistor is changing the load on the pups, and altering the pot's taper. (That's for everyone else viewing). Hey keep me updated on that 7 way switch please, let me know when you hear from your friend/associate regarding it, thanks!
Maybe it can get thru this post with no syntax errors on my part ...
Capacitors block DC once charged, take an isolated cap, clip the probes to it and at first you'll see it's resistance read very low, then the resistance will start to increase more and more as the cap charges, until finally the resistance reaches infinity (or a very high resistance amount). At that point the cap will be blocking the DC from passing thru it. Now I have seen some caps leak DC, but what you're describing here would be a cap that has shorted, or partially so ... That wouldn't be the case here since everything is working correctly.
What you have described here is equal to taking two resistors in series (one volume and one tone), clipping one probe to one end, and the other to the middle connection, and leaving the end of the other resistor floating unconnected ... *But it is connected to ground* you say, thus putting both resistors (pots) in parallel ... yes, but it's connected to ground by *thru a capacitor* That cap looks like an open circuit to the DC, thus the connection is not completed to put them in parallel ... the meter doesn't see the other resistor (pot). Now, it will at first ,until the cap charges ... See?
The only way I can see the meter seeing the other pot , given the wiring and probe placement that you have explained here, is if you had the common probe (black) clipped to ground, and the hot probe (red) { the polarity doesn't matter here, only given as a referrence mind you for others viewing this} clipped to the wiper of the one pot with both controls at *10*. However, that would be placing both pots in series with each other, and not in parallel.
This means that the cap is passing DC, completing the parallel circuit between the two pots, with the knobs at 10 the DC has to go thru the resistance of the pots, so that lengthens the charge time of the cap.
Try this ... Disconnect the cap from ground, and leave it disconnected ... then take the readings (that is, if you actually want to check it, otherwise just roll with it). Anyway, that's why they cap should affect the readings, I'm at a loss as to why you are getting the readings that you are; However, what you are doing with the resistor is changing the load on the pups, and altering the pot's taper. (That's for everyone else viewing). Hey keep me updated on that 7 way switch please, let me know when you hear from your friend/associate regarding it, thanks!
Maybe it can get thru this post with no syntax errors on my part ...
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