All of my guitars are HH\2vol\3way. The pickups obviously got to the pots and the pots to the switch. Are you guys running the capacitor in series with the pickup or parallel between the pickup lug and switch lug on the pot?
A treble bleed is a cap sometimes used with a resistor between the two lugs on the volume pot. It keeps the sound from getting muddy as you turn down the volume.
If you are trying to make the pickups less "boomy" then you'd run a cap in series with the pickup, creating a high-pass filter.
The Kinman mod is very good. It uses (usually) a .001uf cap in series with the resister (instead of in parallel with the resister). This mod keeps the treble consistent through the full volume range.
Then there is the Ibanez mod which effectively boosts the treble at low volume - below 1/2. This mod uses only a cap (no resister) with a value of 330 pf (100 - 500 pf).
Cool guys, yeah I am trying to tame the low end on a brand new Dean Tyrant pickup. It sounds AMAZING, but the low end is a bit much I a string through body all mahogany guitar.
A treble bleed mod won't tame low end, it only keeps highs in the signal from being cut off as you roll the volume down. For too much low end, try lowering the pickup, and raising the screws just a little bit.
This is what I'd do, except I'd put a trim pot in place of the 500k resistor so that I could dial in the amount of bass attenuation. I'd think the 500k resistor would be a little strong, that's going to put a lot of emphasis on the capacitor.
This is what I'd do, except I'd put a trim pot in place of the 500k resistor so that I could dial in the amount of bass attenuation. I'd think the 500k resistor would be a little strong, that's going to put a lot of emphasis on the capacitor.
Actually, I first did this using a trimpot. 500k is what worked best, so I just made it a resistor. It's a very subtle affect. The 500k seems like a lot, but it isn't. Remember, its job is to limit current. A typical pickup generates a tiny amount of current, so the voltage drop across 500k is equally as tiny. You aren't really attenuating much.