But I'm not talking about overdrive at all. Even played dead-squeaky clean, my tube amps just melt all the SS's I've ever tried. In fact, especially when played clean.
Headroom is a function of design, not device type. I would posit that the majority of SS guitar amps are price-point designs. Look at something SS where cost is less of an object and they'll compare positively. The first-series SS Sunn amps, for example.
Headroom is a function of design, not device type. I would posit that the majority of SS guitar amps are price-point designs. Look at something SS where cost is less of an object and they'll compare positively. The first-series SS Sunn amps, for example.
RMS power is about 2.5 times that of peak/peak power. Tube amps are rated in terms of RMS.
A 50w RMS amp has much more power than a 50w peak amp.Huh? RMS is far LESS than peak.
Stevo said:No one has mentioned RMS power? :smack:
RMS power is about 2.5 times that of peak/peak power. Tube amps are rated in terms of RMS.
The factor of Root Mean Square comes from a calculus integral that deals with sine waves. Basically, you can convert peak to peak power to RMS power by multiplying half of the sine wave by the square root of 1/2 (roughly 0.707)
This is also the method used to find the 'DC equivalent' of a sine wave. If you fully rectify a sine wave and filter it, then you create DC with a value of half the AC voltage times 0.707.
Stevo said:A 50w RMS amp has much more power than a 50w peak amp.
Oh no...not a diatribe on interstices and boundary effects....
:fing25: I studied electronic engineering in school and I have built amplifiers. I had to derive all mathematical calculations before building circuits. If any one wants to know how to derive RMS from calculus integrals, then please let me know.you might want to read up on peak vs RMS.
Good point, especially from someone who actually knows what's up :smokin:Play!!!..and don't worry about stuff lke this!..![]()
:fing25: I studied electronic engineering in school and I have built amplifiers. I had to derive all mathematical calculations before building circuits. If any one wants to know how to derive RMS from calculus integrals, then please let me know.
Root Mean Square applied to a sine wave. Call it what you want, but the sine wave represents power (amplitude which is applied to resistance and creates current) and the RMS represents a derived value of that wave.Then of course you know that there is no such thing as "RMS power".