The the frequency of a vibrating string (the pitch) depends on the length (nut to bridge), the tension and the weight of the string following the formula shown here:
http://hyperphysics.phy-astr.gsu.edu/hbase/Waves/string.html
This formula shows that a reverse headstock has no effect on the tension needed to reach the desired pitch (the length from bridge to nut is the same and if the weight of the string is the same then the same tension is needed even if the tuner post was 2 feet beyond the nut.
You might think OK so if the tension is the same then it makes no difference but there is another aspect i.e. when you play a note or do a string bend then you will effectively be stretching the total string length between the bridge and the tuner post (not the nut) and now the effect of the total string length (excluding locking nuts) comes into play. If the whole string is longer it will feel lighter and easier to fret or bend a note. The same applies when you wrap a string over the stop tail rather than just passing it straight through.
So with the reverse headstock the balance and feel will change. The low E will feel slacker and the high E will feel tighter because you have switched round their total length (bridge to tuner post) so now the low E is longer in total and the high E is shorter.
Barrie (Elderwood Guitars)
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