The Varitone switch is selecting between various passive filiter networks. These remove progressively more of the signal generated by the pickups. By definition, passive tone cutting will reduce the overall signal level. This is an intentional part of the design. <shrug>
I only experience significant volume reduction in the last 2 positions of my BluesHawk's Varitone. These are supposedly the single-coil fender-sounding positions.
Anyway, 1st position is Varitone-off, so you don't have to cut any wires for it to be bypassed. Just leave it at no. 1. and have fun ... your guitar should sound excellent as is.
DoDo
Great replies gents, many thanks. I tend to agree that it's a flawed design but overall a beautiful guitar. A volume pedal may solve the problem, but who wants to bother with a volume pedal? I may just cut the wire and revert it back to a good-looking 335 with nice parrellogram inlays. The tone in position 1 is great, the 57 Classics do a fine job.
Lew - how are you doing?
Mike.
Here is the graphic at the link I previously posted:
![]()
Just for easier viewing, I completely removed the Stereo Varitone graphic and cropped the monaural graphic and just left the Varitone circuit.
It seems to me that even when the switch is in the #1 "off" position, the Varitone is still "loading" the signal because the "hot" connection goes through the 10 "Meg" resistors, through the capacitors, through the inductor and out to ground.
Granted those are 10 Meg resistors so it isn't going to be totally influenced but some degradation must occur.
Also notice that when the switch is in any of the "working" positions, the signal first goes through a 100 K resistor. This is probably used to diminish switch "pops" but this no doubt also contributes to some volume loss.
Much, much better. I feel 10 years younger. The chemotherapy makes me sick as a dog for several days a month but we're kicking this cancer's butt!Thanks for asking!
![]()
Here is the graphic at the link I previously posted:
![]()
Just for easier viewing, I completely removed the Stereo Varitone graphic and cropped the monaural graphic and just left the Varitone circuit.
It seems to me that even when the switch is in the #1 "off" position, the Varitone is still "loading" the signal because the "hot" connection goes through the 10 "Meg" resistors, through the capacitors, through the inductor and out to ground.
Granted those are 10 Meg resistors so it isn't going to be totally influenced but some degradation must occur.
Also notice that when the switch is in any of the "working" positions, the signal first goes through a 100 K resistor. This is probably used to diminish switch "pops" but this no doubt also contributes to some volume loss.